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> > Wipro paper(System software)

> > July-1997

> > ------------

> > 

> > PART --A

> > ------------------------------------------------------

> > 1) abcD+abcd+aBCd+aBCD

> >    then the simplified function is

> >    ( Capital letters are copliments of corresponding letters

> >      A=compliment of a)

> > 

> >   [a] a   [b] ab  [c] abc  [d] a(bc)* [e] mone

> >   (bc)*=compliment of bc

> > 

> >   Ans:  e

> > 

> > -------------------------------------

> > 2) A 12 address lines maps to the memory of

> > 

> >  [a] 1k bytes  [b] 0.5k bytes [c] 2k bytes  [d] none

> > 

> >  Ans: b

> > 

> > ----------------------------------------

> > 3) In a processor these are 120 instructions . Bits needed to

impliment

> >    this instructions

> >    [a] 6  [b] 7  [c] 10  [d] none

> > 

> >   Ans: b

> > 

> > -----------------------------------------

> > 4) In 8085 microprocessor READY signal does.which of the following

> >    is incorrect statements

> >    [a]It is input to the microprocessor

> >    [b] It sequences the instructions

> > 

> >   Ans : b

> > ----------------------------------------

> > 

> > 5) Return address will be returned by function to

> >   [a] Pushes to the stack by call

> >   Ans : a

> > ------------------------------------------

> > 6)

> >    n=7623

> >    {

> >         temp=n/10;

> >         result=temp*10+ result;

> >        n=n/10

> >    }

> > 

> > Ans : 3267

> > ----------------------------------------------

> > 7) If A>B then

> >       F=F(G);

> >    else B>C then

> >       F=G(G);

> >    in this , for 75% times A>B and 25% times B>C then,is 10000

> > instructions

> >    are there ,then the ratio of F to G

> >    [a] 7500:2500  [b]  7500:625  [c] 7500:625 if a=b=c else

> >                                      7500:2500

> > --------------------------------------------------

> > 8) In a compiler there is 36 bit for a word and to store a character

> > 8bits are

> > needed. IN this to store

> >  a character two words are appended .Then for storing a K characters

> > string,

> >  How many words are needed.

> >  [a] 2k/9  [b] (2k+8)/9  [c]  (k+8)/9 [d] 2*(k+8)/9 [e] none

> > 

> >  Ans: a

> > ---------------------------------------------------------

> > 9) C program code

> > 

> >    int zap(int n)

> >    {

> >     if(n<=1)then zap=1;

> >     else  zap=zap(n-3)+zap(n-1);

> >    }

> >    then the call zap(6) gives the values of zap

> >    [a] 8  [b]  9  [c] 6  [d]  12  [e] 15

> > 

> >   Ans: b

> > ---------------------------------------------------------------

> > 

> > 

> > PART-B

> > -------

> > 1) Virtual memory size depends on

> >    [a] address lines    [b] data bus

> >    [c] disc space       [d] a & c    [e] none

> > 

> >  Ans :  a

> > -----------------------------------------------

> > 2) Critical section is

> >    [a]

> >    [b] statements which are accessing shared resourses

> >    Ans : b

> > -------------------------------------------------

> > 

> > 3) load a

> >    mul  a

> >    store t1

> >    load  b

> >    mul   b

> >    store t2

> >    mul t2

> >    add t1

> > 

> >   then the content in accumulator is

> > 

> > Ans : a**2+b**4

> > ---------------------------------------------------

> > 4) question (3) in old paper

> > 5) q(4) in old paper

> > 6) question (7) in old paper

> > 7) q(9) in old paper

> > ------------------------------

> > 

> >

> >

> >               WIPRO INFOTECH

 

 

------------------------------------------------------------------------------

Date: July 1997

------------------------------------------------------------------------------

This paper have two sections

each paper contains 10 questions each.

-----------------------------------------------------------------------------

1) abcD+abcd+aBCd+aBCD

   then the simplified function is

   ( Capital letters are copliments of corresponding letters

     A=compliment of a)

 

  [a] a   [b] ab  [c] abc  [d] a(bc)* [e] mone

  (bc)*=compliment of bc

 

  Ans:  e

 

-------------------------------------

2) A 12 address lines maps to the memory of

 

 [a] 1k bytes  [b] 0.5k bytes [c] 2k bytes  [d] none

 

 Ans: b

 

----------------------------------------

3) In a processor these are 120 instructions . Bits needed to

impliment

   this instructions

   [a] 6  [b] 7  [c] 10  [d] none

 

  Ans: b

 

-----------------------------------------

4) In 8085 microprocessor READY signal does.which of the

following

   is incorrect statements

   [a]It is input to the microprocessor

   [b] It sequences the instructions

 

  Ans : b

----------------------------------------

 

5) Return address will be returned by function to

  [a] Pushes to the stack by call

  Ans : a

------------------------------------------

6)

   n=7623

   {

      temp=n/10;

      result=temp*10+ result;

       n=n/10

   }

 

Ans : 3267

----------------------------------------------

7) If A>B then

      F=F(G);

   else B>C then

      F=G(G);

   in this , for 75% times A>B and 25% times B>C then,is 10000

instructions

   are there ,then the ratio of F to G

   [a] 7500:2500  [b]  7500:625  [c] 7500:625 if a=b=c else

                             7500:2500

 

Ans : b

--------------------------------------------------

8) In a compiler there is 36 bit for a word and to store a

character 8bits are needed. IN this to store

 a character two words are appended .Then for storing a K

characters string,

 How many words are needed.

 [a] 2k/9  [b] (2k+8)/9  [c]  (k+8)/9 [d] 2*(k+8)/9 [e] none

 

 Ans: b

---------------------------------------------------------

9) C program code

  

   int zap(int n)

   {

    if(n<=1)then zap=1;

    else  zap=zap(n-3)+zap(n-1);

   }

   then the call zap(6) gives the values of zap

   [a] 8  [b]  9  [c] 6  [d]  12  [e] 15

 

  Ans: b

---------------------------------------------------------------

 

 

PART-B

-------

1) Virtual memory size depends on

   [a] address lines    [b] data bus

   [c] disc space       [d] a & c    [e] none

 

 Ans :  a

-----------------------------------------------

2) Critical section is

   [a]

   [b] statements which are accessing shared resourses

   Ans : b

-------------------------------------------------

 

3) load a

   mul  a

   store t1

   load  b

   mul   b

   store t2

   mul t2

   add t1

 

  then the content in accumulator is

 

Ans : a**2+b**4

---------------------------------------------------

4) question (3) in old paper

5) q(4) in old paper

6) question (7) in old paper

7) q(9) in old paper

------------------------------

   

 

Sankalp Verma

B.E.(IV) Metallurgical and Materials Engineering

UNIVERSITY OF ROORKEE

Click here to go the paper of Infosys:infosys.htm

 



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